SOLUTION: A baseball player throws a ball to another player on her team. The ball is released from a height of 6 feet and reaches its maximum height of 26 feet 2 seconds after being released

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Question 1117109: A baseball player throws a ball to another player on her team. The ball is released from a height of 6 feet and reaches its maximum height of 26 feet 2 seconds after being released. Determine how long the ball is in the air?
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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It depends on where the other player caught the ball.


Formulate your problem/(your question) in more accurate way . . .


It is Math - not a baseball.



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A baseball player throws a ball to another player on her team. The ball is released from a height of 6 feet and reaches its maximum height of 26 feet 2 seconds after being released. Determine how long the ball is in the air?
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If the ball is caught at a height of 6 feet, the total flight time would be 4 seconds, but there are some inconsistencies in this.
A time of 2 seconds and 26 ft max ht does not match the gravitational constants on Earth.
Ascending or descending from/to the ground in 2 seconds --> 16t^2 = 64 feet, not 26 feet.
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Maybe it's a badminton shuttlecock, air resistance is a factor, or it is thrown on a planet with gravity greater than Earth's.
Or maybe it's a typo.