SOLUTION: 584 tickets have been sold for the schools play. An adult ticket costs $5 and a student ticket costs $3. The total ticket sales are $2112. Use a system of equations to solve for th
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-> SOLUTION: 584 tickets have been sold for the schools play. An adult ticket costs $5 and a student ticket costs $3. The total ticket sales are $2112. Use a system of equations to solve for th
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Question 1114919: 584 tickets have been sold for the schools play. An adult ticket costs $5 and a student ticket costs $3. The total ticket sales are $2112. Use a system of equations to solve for the number of student tickets that have been sold to the play. Found 2 solutions by ikleyn, addingup:Answer by ikleyn(52781) (Show Source):
It is not a rational way to solve this problem using system of equations.
Since the problem asks for only ONE unknown ("the number of student tickets"), it is much more reasonable, simple and straightforward way
to solve it using a single equation for only one unknown x, which is the number of student tickets.
The equation is
3x + 5*(584-x) = 2112.
3x + 5*584 - 5x = 2112
-2x = 2112 - 5*584 = -808 ====> x = = 404.
Answer. The number of student tickets sold is 404.
You can put this solution on YOUR website! To solve as a system of equations:
Equation for the number of tickets sold:
a + s = 584
multiply all elements in this equation times 5:
5a + 5s = 2920 (1)
Equation for the total $ tickets sold:
5a + 3s = 2112 subtract this equation from (1):
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5a + 5s = 2920
-
5a + 3s = 2112
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0a + 2s = 808
rewrite, since the value of a is 0:
2s = 808
s = 404