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If a^2 + 1 = a, then a^2 - a + 1 = 0.
Multiply both sides by (a+1). You will get a^3 + 1 = 0, or a^3 = -1.
So, the values of "a" that are the roots of the original equation, are the complex cubic roots of (-1).
// If you solve the original equation using the quadratic formula, you will get the same result.
Therefore, a^12 = (a^3)^4 = (-1)^4 = 1, and
a^6 = (a^3)^2 = (-1)^2 = 1.
Thus a^12 + a^6 + 1 = 1 + 1 + 1 = 3.
The answer is 3. Choice b).
Solved.