.
The speed with the wind was
= 300 miles per hour.
It is the sum of the plane speed at no wind "u" and speed of the wind "v":
u + v = 300. (1)
The speed against the wind was
= 240 miles per hour.
It is the difference of the plane speed at no wind "u" and speed of the wind "v":
u - v = 240. (2)
Now add equations (1) and (2). You will get
2u = 300 + 240 = 540, which implies u = = 270 mph.
Now substitute it into eq(1) to get
v = 300 - 270 = 30.
Answer. The plain speed at no wind is 270 mph; the wind speed is 30 mph.
Solved.
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It is a typical "tailwind and headwind" word problem.
See the lessons
- Wind and Current problems
- Wind and Current problems solvable by quadratic equations
- Selected problems from the archive on a plane flying with and against the wind
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the section "Word problems", the topic "Travel and Distance problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.