SOLUTION: A family includes 3 kids. Determine the probability that: a. 3 are = 2 boys and one girl b. there are at least one boy c. there are children of both sex d. there is at most one

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Question 1110062: A family includes 3 kids. Determine the probability that:
a. 3 are = 2 boys and one girl
b. there are at least one boy
c. there are children of both sex
d. there is at most one girl
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Look at all of the possibilities there are 8 %282%5E3%29 of them.
BBB
BBG
BGB
BGG
GBB
GBG
GGB
GGG
So then,
a) 2B and 1G: BBG, BGB, GBB - 3 outcomes.
P=3%2F8
b) Let's do it backwards. No boys - GGG - 1 outcome.
The complement is 7.
P=7%2F8
c) Again, use the complement, BBB and GGG - 2 outcomes so,
P=6%2F8=3%2F4
d) So no girls or 1 girl, BBB, BBG, BGB, GBB, 4 outcomes,
P=4%2F8=1%2F2