SOLUTION: A projectile is fired from the ground with initial velocity of 960 ft/sec, at an angle of 30° above the horizontal. If the height as a function of time t is given by h(t)=480t–16t^
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Question 1109691: A projectile is fired from the ground with initial velocity of 960 ft/sec, at an angle of 30° above the horizontal. If the height as a function of time t is given by h(t)=480t–16t^2, find its maximum height. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A projectile is fired from the ground with initial velocity of 960 ft/sec, at an angle of 30° above the horizontal. If the height as a function of time t is given by h(t)=480t–16t^2, find its maximum height.
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h(t)=480t–16t^2
Max height is the vertex of the parabola at t = -b/2a
t = -480/-32 = 15 seconds
--> h(15)
