SOLUTION: Can you show me how to use u substitution version of the chain role to find {{{dy/dx}}} of y=(sin^5)x

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Question 1088416: Can you show me how to use u substitution version of the chain role to find dy%2Fdx of y=(sin^5)x
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
dy%2Fdx of y=sin^5(x)
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y' = 5sin%5E4%28x%29%2Acos%28x%29