SOLUTION: A chemist needs 2 liters of a 26% acid solution. He has an 18​% solution and a 50​% solution available to form the mixture. How much of each should be used to form the
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Question 1086591: A chemist needs 2 liters of a 26% acid solution. He has an 18% solution and a 50% solution available to form the mixture. How much of each should be used to form the 26% solution? Found 4 solutions by mathmate, josgarithmetic, josmiceli, MathTherapy:Answer by mathmate(429) (Show Source):
You can put this solution on YOUR website! Question:
A chemist needs 2 liters of a 26% acid solution. He has an 18% solution and a 50% solution available to form the mixture. How much of each should be used to form the 26% solution?
Solution:
Given solutions at 18% and 50%, need 2L of 26%.
Ratio of 18%:50% = (50-26):(26-18) = 24:8 = 3:1 so 1.5L of 18% + 0.5L of 50%
You can put this solution on YOUR website! Let = liters of the 18% mixture needed
Let = liters of the 50% mixture needed
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(1)
(2)
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(2)
(2)
(2)
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)
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and
(1)
(1)
(1)
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1.5 liters of the 18% mixture are needed
.5 liters of the 50% mixture is needed
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check:
(2)
(2)
(2)
(2)
(2)
OK
You can put this solution on YOUR website! A chemist needs 2 liters of a 26% acid solution. He has an 18% solution and a 50% solution available to form the mixture. How much of each should be used to form the 26% solution?
Correct answer:
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