SOLUTION: For 68 days in a row, a person receives twice the number of pennies as the day before (day 1 - .01, day 2 - .02, day 3 - .04, day 4 - .08...........). What is the sum of the total

Algebra ->  Finance -> SOLUTION: For 68 days in a row, a person receives twice the number of pennies as the day before (day 1 - .01, day 2 - .02, day 3 - .04, day 4 - .08...........). What is the sum of the total      Log On


   

Question 107244: For 68 days in a row, a person receives twice the number of pennies as the day before (day 1 - .01, day 2 - .02, day 3 - .04, day 4 - .08...........). What is the sum of the total 68 days?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
2^0+2^1+2^2+2^3...+2^67=?

this is much easier to see in binary

1111111111111111111111111111111111111111111111111111111111111111111
...is the same as...
10000000000000000000000000000000000000000000000000000000000000000000-1


(look at the source)