SOLUTION: A man has a rectangular garden. One length of garden lies along a patio wall. However, the rest of the garden is enclosed by 50 feet of fence.If the length of the garden is 3 times

Algebra ->  Finance -> SOLUTION: A man has a rectangular garden. One length of garden lies along a patio wall. However, the rest of the garden is enclosed by 50 feet of fence.If the length of the garden is 3 times      Log On


   

Question 1070752: A man has a rectangular garden. One length of garden lies along a patio wall. However, the rest of the garden is enclosed by 50 feet of fence.If the length of the garden is 3 times its width. What is the area of the garden?
Thank you for the help!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +L+ = the length of garden parallel to the wall
Let +W+ = the width of the garden
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You are given that:
+L+%2B+2W+=+50+ ft
and
+L+=+3W+
so
+3W+%2B+2W+=+50+
+5W+=+50+
+W+=+10+ ft
and
+L+=+3W+
+L+=+3%2A10+
+L+=+30+ ft
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Area = +L%2AW+
Area = +30%2A10+
Area = +300+ ft2