SOLUTION: find the equation of the tangent line for y=x^3-3x+1 at point (2,3)

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Question 1070565: find the equation of the tangent line for
y=x^3-3x+1
at point (2,3)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The derivative of x^3-3x+1=3x^2-3
When x=2, the slope is 9.
point slope formula at (2,3) with slope 9 is y-y1=m(x-x1), m the slope and (x1,y1) the point
y-3=9*(x-2)
y=9x-15
graph%28300%2C300%2C-10%2C10%2C-20%2C20%2Cx%5E3-3x%2B1%2C9x-15%29
graph%28300%2C300%2C-2%2C3%2C-10%2C20%2Cx%5E3-3x%2B1%2C9x-15%29