SOLUTION: Two cyclists leave a city at the same​ time, one going east and the other going west. The west bound cyclist bikes at 18 mph faster than the east bound cyclist. After 5 hours

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Question 1070458: Two cyclists leave a city at the same​ time, one going east and the other going west. The west bound cyclist bikes at 18 mph faster than the east bound cyclist. After 5 hours they are 180 miles apart. How fast is each cyclist​ riding?
Found 2 solutions by addingup, josgarithmetic:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
5x+5x+18 = 180
10x = 162
x = 16.2 this is the speed of the slower cyclist
x+18 = 16.2+18 = 34.2 is the speed of the faster cyclist

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Eastbound cyclist: r%2A5
Westbound cyclist: %28r%2B18%29%2A5
Distance between the cyclists is given as 180 miles:
5r%2B5%28r%2B18%29=180.


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5r%2B5r%2B90=180
10r=180-90
10r=90
highlight%28r=9%29-----speed of the eastbound cyclist

r%2B18=highlight%2827%29------speed of the westbound cyclist