SOLUTION: The second side of a triangular deck is 4 feet longer than the shortest side and a third side that is 4 feet shorter than twice the length of the shortest side. If the perimeter of
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Question 1070181: The second side of a triangular deck is 4 feet longer than the shortest side and a third side that is 4 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 48 feet, what are the lengths of the three sides?
Thank you SO much for the help! Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! let s = the length of the shortest side
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Write an equation for each statement
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The second side of a triangular deck is 4 feet longer than the shortest side
(s+4) = the 2nd side
and a third side that is 4 feet shorter than twice the length of the shortest side.
(2s-4) = the 3rd side
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If the perimeter of the deck is 48 feet, what are the lengths of the three sides?
s + (s+4) + (2s-4) = 48
Combine like terms
s + s + 2s + 4 - 4 = 48
4s = 48
s = 48/4
s = 12 ft is the shortest side
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I'll let you find the 2nd and 3rd sides, ensure they add up to 48