SOLUTION: How many cups of pure water should be mixed with 1.5 cups of a 80​% acid solution to dilute it into a 22​% acid​ solution?
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Question 1069953: How many cups of pure water should be mixed with 1.5 cups of a 80% acid solution to dilute it into a 22% acid solution?
? cups (Type an integer or a decimal.)
A rectangular solar panel has a length that is 11 inches shorter than 3 times its width. If the perimeter of the panel is 178 inches, what are the dimensions of the panel?
The width of the panel is
? inches.
(Simplify your answer.) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! How many cups of pure water should be mixed with 1.5 cups of a 80% acid solution to dilute it into a 22% acid solution?
:
let w = amt of pure water
.8(1.5) = .22(w+1.5)
1.2 = .22w + .33
1.2 - .33 = .22w
.87 = .22w
w = .87/.22
w = 3.95 cups of water required
:
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A rectangular solar panel has a length that is 11 inches shorter than 3 times its width.
L = 3W - 11
If the perimeter of the panel is 178 inches, what are the dimensions of the panel?
2L + 2W = 178
simplify, divide by 2
L + W = 89
replace L with (3W-11), (equation from the first statement)
(3W-11) + W = 89
3W + W = 89 + 11
4W = 100
W = 100/4
W = 25 inches is the width
then
3(25) - 11 = 64 inches is the width
