SOLUTION: Larry Mitchell invested part of his $17,000 advance at 5% annual simple interest and the rest at 3% annual simple interest. If his total yearly interest from both accounts was $73

Algebra ->  Finance -> SOLUTION: Larry Mitchell invested part of his $17,000 advance at 5% annual simple interest and the rest at 3% annual simple interest. If his total yearly interest from both accounts was $73      Log On


   



Question 1068554: Larry Mitchell invested part of his $17,000 advance at 5% annual simple interest and the rest at 3% annual simple interest. If his total yearly interest from both accounts was $730​,
find the amount invested at each rate.
What is the amount invested at 5%? And what is the amount invested at 3%?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.A%2BB=17000
.
.
0.05A%2B0.03B=730
Multiply both sides by 100.
2.5A%2B3B=73000
Multiply eq. 1 by 3 and subtract from eq. 2 to eliminate B,
5A%2B3B-3A-3B=73000-51000
2A=22000
Solve for A.
Then use either equation to solve for B.