Question 1065159: The total amount of water in two containers is 35 quarts. If 7 quarts is poured from the container with less water into the container with more water, the container with more water will have 4 times as much water as the other container. How many quarts are in the container with less water?
Found 2 solutions by JulietG, MathTherapy:
Answer by JulietG(1812)   (Show Source):
You can put this solution on YOUR website! Let A be the first container (the one with more water)
Let B be the second container
A + B = 35
A - 7 = 4(B+7)
A-7 = 4B+28
A = 4B+35
Substitute that value into the first equation.
A + B = 35
(4B+35) + B = 35
5B + 35 = 35
5B = 0
B = 0
Tricky question! There was nothing in B. Which means A had 35 quarts. When A transferred 7 of its 35, it now had 28. B now had 7. 7 is 4 times 28.
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ETA: Thank you for your clarification. You are correct (if ill-mannered.) I have written to the student to let him know.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! The total amount of water in two containers is 35 quarts. If 7 quarts is poured from the container with less water into the container with more water, the container with more water will have 4 times as much water as the other container. How many quarts are in the container with less water?
The container with less water started with: 
FYI: No TRICK to this!! It's pretty straight-forward.
Ms. JULIETG
No, it's not the correct answer. You misread the problem. Note that 7 quarts was poured from the container with LESS water (14 - 7 = 7), into the container
with MORE water (21 + 7), which makes the one with less, now with 7 quarts, and the one with more, now with 28 quarts, which means that the one with MORE
(28 quarts), still has more, and contains 4 times (4 * 7) the one with LESS (7).
You seem to have poured from the container with MORE into the container with LESS, but it should be the other way around. This is how I understand it!
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