SOLUTION: Suppose that a cyclist began a 330 mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the

Algebra ->  Finance -> SOLUTION: Suppose that a cyclist began a 330 mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the       Log On


   



Question 1060436: Suppose that a cyclist began a
330
mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after
5.5
hr and the car traveled
32.4
mph faster than the​ bicycle, find the average rate of each.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = distance in miles the west - east cyclist
travels until meeting car
-----------------------------------------
+330+-+d+ = distance in miles east - west car
travels until meeting cyclist
-----------------------------------------
Let +s+ = the speed of the cyclist in mi/hr
+s+%2B+32.4+ = the speed of the car in mi/hr
------------------------------------------
Equation for W - E cyclist
(1) +d+=+s%2A5.5+
-------------------------
Equation for E - W car:
(2) +330+-+d+=+%28+s+%2B+32.4+%29%2A5.5+
-----------------------------------
Substitute (1) into (2)
(2) +330+-+5.5s+=+%28+s+%2B+32.4+%29%2A5.5+
(2) +330+-+5.5s+=+5.5s+%2B+178.2+
(2) +11s+=+330+-+178.2+
(2) +11s+=+151.8+
(2) +s+=+13.8+
and
+s+%2B+32.4+=+46.2+
-----------------------
The bike's ave. rate is 13.8 mi/hr
The car's ave. rate is 46.2 mi/hr
-----------------------------
check:
(1) +d+=+s%2A5.5+
(1) +d+=+13.8%2A5.5+
(1) +d+=+75.9+
and
(2) +330+-+d+=+%28+s+%2B+32.4+%29%2A5.5+
(2) +330+-+d+=+%28+13.8+%2B+32.4+%29%2A5.5+
(2) +330+-+d+=+46.2%2A5.5+
(2) +d+=+330+-+254.1+
(2) +d+=+75.9+
OK