SOLUTION: would you plz solve this problem? Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten, and the rest were either ripe or unripe. There were 18 more ripe oranges than unripe

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Question 1057120: would you plz solve this problem?
Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten, and the rest were either ripe or unripe. There were 18 more ripe oranges than unripe oranges. Find the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges.
Thank you.
Found 2 solutions by josmiceli, math_helper:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+84+-+24+=+60+ oranges were not rotten
Let +x+ = the number of unripe oranges
+x+%2B+18+ = the number of ripe oranges
---------------------------------------------
+x+%2B+x+%2B+18+=+60+
+2x+=+42+
+x+=+21+
and
+x+%2B+18+=+39+
----------------------
The ratio of ripe to rotten to unripe is:
39:24:21


Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

b = number rotten = 24 (given)
r = number ripe
u = number unripe
r = u + 18 ("18 more ripe than unripe")
r + u = 84-24 ("84 oranges, 24 were rotten, the rest were either ripe or unripe")
Substitute the right hand side of the top equation into the bottom:
(u + 18) + u = 84-24
2u + 18 = 60
2u = 42
u = 21 —> r = 39
ripe/rotten = 39/24 = 1.000/0.615 = 1.626/1
ripe/unripe = 39/21 = 1.000/0.538 = 1.859/1