Question 1054658: P, Q and R start from the same place X at (a) kmph, (a+b) kmph and (a+2b) kmph respectively.
If Q starts p hours after P, how many hours after Q should R start, so that both Q and R overtake P at the same time?
Answer is pa/a+2b
This chapter is of time speed and distance
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! EDIT: Same question asked again, and answered about a week later, Nov. 4, 2016. Solution found was different than here at the bottom. See the posted response to Question #1055890.
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No. That cannot be correct.
From question posting 1054641:
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The order in which each agent starts its trip is P, Q, R. The agent traveling for the shortest time will be R.
Interesting no time values are given; only variables must be kept for all numbers.
RATE TIME DISTANCE
P begins a t+p d
Q begins a+b p d
R begins a+2b x d
We can only expect we do NOT know d, t, or x. We know none of them. We should assume a, a+b, a+2b, and p are constants, although not given other than as those variables.
Based on constant travel rate rule, RT=D we can form a system of equations.
The question asks essentially for solution to x. Could you try to solve for d, first, and use it to solve for x? Did you possibly miss any given information from your problem description?
I see only this at best:
 and the only unknown variable is x.
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To finish that work,  or  .
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