SOLUTION: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 35% and the third contains  55%. He wants to use all thre

Algebra ->  Finance -> SOLUTION: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 35% and the third contains  55%. He wants to use all thre      Log On


   

Question 1039019: A chemist has three different acid solutions. The first acid solution contains
25% acid, the second contains
35% and the third contains

55%. He wants to use all three solutions to obtain a mixture of
90 liters containing
45% acid, using
3 times as much of the

55% solution as the

35% solution. How many liters of each solution should be used?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x,y,z for 25%,35%,55% acid solutions

z=3y is given in description.

Pure acid in the result solution will be 45*90, counting in percent.

system%2825x%2B35y%2B55z=45%2A90%2Cx%2By%2Bz=90%2Cz=3y%29

Study that system and attend it to understand. Once understood, solve the system.