SOLUTION: Let g(x)n = x(3x-9)^3, find (dg/dx)
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Question 1034457
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Let g(x)n = x(3x-9)^3, find (dg/dx)
Answer by
Boreal(15235)
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Chain rule
x*3(3x-9)^2(3)+(3x-9)^3; first * derivative of second+second * derivative of first. Have to do the derivative of (3x-9).
(3x-9)^2{9x)+(3x-9)}
=(3x-9)^2(12x-9)