SOLUTION: given f(x) = (x^3 + 3x + 2)/(x^2-1), find f'(x)

Algebra ->  Finance -> SOLUTION: given f(x) = (x^3 + 3x + 2)/(x^2-1), find f'(x)       Log On


   



Question 1034456: given f(x) = (x^3 + 3x + 2)/(x^2-1), find f'(x)
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
given f(x) = (x^3 + 3x + 2)/(x^2-1), find f'(x)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~`

Use the derivative rule for the quotient: 


if  f(x) = u%28x%29%2Fv%28x%29,  then  f'(x) = (u'*v - u*v')/v^2.   (1)


In your case  u = x%5E3+%2B+3x+%2B+2  and  v = x%5E2-1,  so

u' = 3x%5E2+%2B3  and  v' = 2x.


Substitute it into (1) and simplify.


You are CALCULUS !