SOLUTION: The circle with center at O is circumscribed about the triangle and OD is drawn perpendicular to BC. What is the relation of BOD to a? Using the right triangle BDO, prove sin a = a
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Question 1034436: The circle with center at O is circumscribed about the triangle and OD is drawn perpendicular to BC. What is the relation of BOD to a? Using the right triangle BDO, prove sin a = a/2R. with the necessary additional construction, prove the law of sines. Answer by ikleyn(52781) (Show Source):
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The circle with center at O is circumscribed about the triangle and OD is drawn perpendicular to BC.
What is the relation of BOD to a? Using the right triangle BDO, prove sin a = a/2R. with the necessary
additional construction, prove the law of sines.
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