SOLUTION: In the right triangle ABC, with a= 30 degrees, AB= 2. D is chosen on AC so that DC=BC, and from D a line is drawn perpendicular to AB, meeting AB at K. Show DBK = 15degrees and by

Algebra ->  Finance -> SOLUTION: In the right triangle ABC, with a= 30 degrees, AB= 2. D is chosen on AC so that DC=BC, and from D a line is drawn perpendicular to AB, meeting AB at K. Show DBK = 15degrees and by       Log On


   



Question 1034431: In the right triangle ABC, with a= 30 degrees, AB= 2. D is chosen on AC so that DC=BC, and from D a line is drawn perpendicular to AB, meeting AB at K. Show DBK = 15degrees and by finding the lengths of the various lines.
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
In the right triangle ABC, with a= 30 degrees, AB= 2. D is chosen on AC so that DC=BC, and from D a line is drawn
perpendicular to AB, meeting AB at K. Show DBK = 15degrees and by finding the lengths of the various lines.
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Your formulation is very inaccurate and therefore unclear.

Is AB a leg or the hypotenuse?

Is BC a leg or the hypotenuse?

These things should be clear immediately from the formulation,
and the reader should not make hypotheses about it.

So, re-formulate and re-post please.