SOLUTION: Write the standard form of the equation of the hyperbola for which a = 5, b = 6, the transverse axis is horizontal, and the center is at the origin.
x²/36 - y²/25 = 1
x²/25 - y
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-> SOLUTION: Write the standard form of the equation of the hyperbola for which a = 5, b = 6, the transverse axis is horizontal, and the center is at the origin.
x²/36 - y²/25 = 1
x²/25 - y
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Question 1034390: Write the standard form of the equation of the hyperbola for which a = 5, b = 6, the transverse axis is horizontal, and the center is at the origin.
x²/36 - y²/25 = 1
x²/25 - y²/36 = 1
y²/36 - x²/25 = 1
y²/25 - x²/36 = 1 Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! x²/25 - y²/36 = 1.
The transverse being horizontal means the the sign before the y-term must be minus. The a constant will correspond to the x-term, being associated with the transverse axis.
