SOLUTION: Write the standard form of the equation of the circle that is tangent to the y-axis and has its center at (3, -2).
(x - 3)² + (y + 2)² = 9
(x + 3)² + (y - 2)² = 9
(x - 3)² + (
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-> SOLUTION: Write the standard form of the equation of the circle that is tangent to the y-axis and has its center at (3, -2).
(x - 3)² + (y + 2)² = 9
(x + 3)² + (y - 2)² = 9
(x - 3)² + (
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Question 1034377: Write the standard form of the equation of the circle that is tangent to the y-axis and has its center at (3, -2).
(x - 3)² + (y + 2)² = 9
(x + 3)² + (y - 2)² = 9
(x - 3)² + (y + 2)² = 4
(x + 2)² + (y - 3)² = 4 Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! Given point is in Q4, and you can easily identify the distance from center (3,-2) to y-axis, being 3. Just fit into the standard form from that.
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