SOLUTION: A particle is moving with velocity v(t) = t2 – 9t + 18 with distance, s measured in meters, left or right of zero, and t measured in seconds, with t between 0 and 8 seconds inclusi

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Question 1029785: A particle is moving with velocity v(t) = t2 – 9t + 18 with distance, s measured in meters, left or right of zero, and t measured in seconds, with t between 0 and 8 seconds inclusive. The position at time t = 0 sec is 1 meter right of zero, that is, s(0) = 1.
what is:
The average velocity over the interval 0 to 8 seconds
&
The instantaneous velocity and speed at time 5 secs
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Average velocity over the interval 0 to 8 seconds = %281%2F8%29int%28t%5E2-9t%2B18%2C+dt%2C+0%2C8%29+
= meters per second.
The instantaneous velocity = dv%28t%29%2Fdt+=+2t+-+9 ==>The instantaneous velocity and speed at time 5 secs is 2*5 - 9 = 1 meter per second.