SOLUTION: The velocity in ft/sec of a particle is given by v(t) = −16t + 2. Find the position function s(t), of the particle if it has an initial position s(0) = 6 feet.
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Question 1029019: The velocity in ft/sec of a particle is given by v(t) = −16t + 2. Find the position function s(t), of the particle if it has an initial position s(0) = 6 feet. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The velocity in ft/sec of a particle is given by v(t) = −16t + 2. Find the position function s(t), of the particle if it has an initial position s(0) = 6 feet.
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Velocity is the 1st derivative of position.
v(t) = -16t + 2
Integrate wrt t:
s(t) = -8t^2 + 2t + C
s(0) = C = 6
s(t) = -8t^2 + 2t + 6
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