SOLUTION: a and b are positive integers. Find −2a+3b if a^3b^2=72

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Question 1028099: a and b are positive integers. Find −2a+3b if a^3b^2=72
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
72+=+2%5E3%2A3%5E2 and the uniqueness of prime factorization of numbers ==> a = 2 and b = 3 ==> -2a+3b = -2*2 + 3*3 = 5.