Question 102776This question is from textbook Algebra:Structure and Method
: How do I set up this problem to solve it?
Nine cartons of juice cost the same as 5 fruit cups. Also, one fruit cup costs $0.50 more than one bowl of soup, while one bowl of soup costs $0.50 more than one carton of juice. What would be the cost of each item: a carton of juice, a fruit cup, and a bowl of soup?
This question is from textbook Algebra:Structure and Method
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Nine cartons of juice cost the same as 5 fruit cups. Also, one fruit cup costs $0.50 more than one bowl of soup, while one bowl of soup costs $0.50 more than one carton of juice. What would be the cost of each item: a carton of juice, a fruit cup, and a bowl of soup?
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j=juice; f=fruit; s=soup
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EQUATIONS:
9j=5f
f=s+(1/2)
s=j+(1/2)
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Rearrange:
9j-5f+0s=0
0j+2f-2s=1
2j+0f-2s=-1
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Solution using TI calculator:
j = 1.25
f = 2.25
s = 1.75
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Cheers,
Stan H.
j+0f-2s=-1
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