Since a+b appears twice, let c = a+b
Get a least common denominator of ac
Factor out
So we try to factorize the trinomial like this,
breaking up as the product of and :
It doesn't take too much thinking to know that we
must fill in the blank spaces with c and a to
cause the product to be ac
And if we find the outer and inner products, we
find that we get -aČ-bČ which is -(aČ+bČ).
So that is the correct factorization. All that's
left is to substitute (a+b) for c and simplify:
Removing the inner parentheses we have:
Edwin