SOLUTION: The bullet train in Japan leaves a station at 5 A.M. and travels north at 50 mph. At 6 A.M., a passenger train leaves on a parallel track and travels north at 55 mph. How long will

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Question 1019822: The bullet train in Japan leaves a station at 5 A.M. and travels north at 50 mph. At 6 A.M., a passenger train leaves on a parallel track and travels north at 55 mph. How long will it take the passenger train to overtake the bullet train?
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
What is the bullet train's head start
in mi/hr ?
The difference between 5 AM and 6 AM is 1 hr
+d%5B1%5D+=+50%2A1+
+d%5B1%5D+=+50+ mi
Start a stopwatch when the passenger train leaves
at 6 AM
Let +t+ = time on stopwatch in hrs when
passenger train overtakes the bullet train
Let +d+ = distance in miles passenger train
travels until it catches up with bullet train
------------------------------------
Equation for bullet train:
(1) +d+-+50+=+50t+
Equation for passenger train:
(2) +d+=+55t+
------------------------
Substitute (2) into (1)
(1) +55t+-+50+=+50t+
(1) +5t+=+50+
(1) +t+=+10+
The passenger train overtakes the bullet train
in 10 hrs
--------------
Check:
(2) +d+=+55t+
(2) +d+=+55%2A10+
(2) +d+=+550+
and
(1) +d+-+50+=+50t+
(1) +d+-+50+=+50%2A10+
(1) +d+=+50+%2B+500+
(1) +d+=+550+
OK

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The speed of the Japanese "Bullet train" is apx 200 mi/hr. Not 50.