SOLUTION: The graphs of the two given functions are identical, except for a hole. What are the coordinates of the hole? H(x)=x^2-7x and K(x)= ((x^2-6x^2-7x)/(x+1)) The coordinates of the h

Algebra ->  Finance -> SOLUTION: The graphs of the two given functions are identical, except for a hole. What are the coordinates of the hole? H(x)=x^2-7x and K(x)= ((x^2-6x^2-7x)/(x+1)) The coordinates of the h      Log On


   

Question 1014689: The graphs of the two given functions are identical, except for a hole. What are the coordinates of the hole?
H(x)=x^2-7x and K(x)= ((x^2-6x^2-7x)/(x+1))
The coordinates of the hole are..
Found 2 solutions by solver91311, josgarithmetic:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The graphs of the two functions you presented are not even close to being identical, nor is there a "hole" in either one. You have a typo. Correct it and repost.

John

My calculator said it, I believe it, that settles it

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
K%28x%29=%28x%28x%2B1%29%28x-7%29%29%2F%28x%2B1%29

Undefined and therefore a hole at x=-1.


H(x) would hold that point as legitimately defined, for H%28-1%29=%28-1%29%5E2-7%28-1%29=1%2B7=8.