SOLUTION: An ice cream parlor made $200. They sold cups for $0.60, and cones for $2. How much cups of ice cream did they sell, and how many cones of ice cream did they sell?
I tried divid
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I tried divid
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Question 1013111: An ice cream parlor made $200. They sold cups for $0.60, and cones for $2. How much cups of ice cream did they sell, and how many cones of ice cream did they sell?
I tried dividing $200 by $0.60, but what about the cones?
PLEASE EXPLAIN STEPS Found 2 solutions by josgarithmetic, KMST:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! = number of cups sold = number of cones sold = money (in $) made by selling cups = money (in $) made by selling cones = total money (in $) made by selling cups and cones.
I would expect another piece of information, such as the fact that they served a certain number of customers.
IF the problem stated that servings (between cones and cups) were sold
we would write that , and we would find and .
by solving the system of linear equations --->--->--->--->
--->--->--->--->--->
Since is the only equation you can write from the information given,
we should expect to find more than one solution.
Only fact that and must both be integers keeps the problem from having solutions. <--><-->
For to be an integer, we need } to be an integer,
and for to be an integer, must be a multiple of .
So we take non-negative values for that can be divided by ,
calculate for each value,
and tabulate all the many solutions we find:
(