SOLUTION: If two points of a coordinate system are (a,b) and (c,d) and the point that divides the line which joins the two points in 3:2 ratio is (p,q), {{{p = (2a + 3c)/(3+2)}}} {{{q

Algebra ->  Finance -> SOLUTION: If two points of a coordinate system are (a,b) and (c,d) and the point that divides the line which joins the two points in 3:2 ratio is (p,q), {{{p = (2a + 3c)/(3+2)}}} {{{q       Log On


   



Question 1013064: If two points of a coordinate system are (a,b) and (c,d) and the point that divides the line which joins the two points in 3:2 ratio is (p,q),
p+=+%282a+%2B+3c%29%2F%283%2B2%29
q+=+%282b+%2B+3d%29%2F%283%2B2%29
is the formula to find p and q.
My question is since these formulas are proof in plus coordinates (+a,+b) (+c,+d), how does the formula give the correct answer even when (-a,+b) (+c,+d) (When one coordinate is minus).
I get it.. when we substitute the correct signs of coordinates to the formula, we get the answer. I want to know how does it happen. Thank you.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
There is nothing special about negative coordinates.
They are negative because we set a zero in an arbitrary place,
and arbitrarily decided to what side of that zero we would call the numbers negative numbers.
Your negative numbers are not negative if you set the zero far enough to the negative side.
You can move the coordinate axis so that every coordinate you are using is positive, and the distances and relative positions from one point to another will not change.
You could even flip one or both axes around to point in the opposite direction, and distances and relative positions of those points would not change.

Why the formula is like that is a different story.