SOLUTION: Find the slope of the graph of the relation 2x3 − 3xy + y3 = −1 at the point (2, −3).
negative eleven sevenths
5 over 7
negative 1 over 3
4 over 3
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-> SOLUTION: Find the slope of the graph of the relation 2x3 − 3xy + y3 = −1 at the point (2, −3).
negative eleven sevenths
5 over 7
negative 1 over 3
4 over 3
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Question 1001214: Find the slope of the graph of the relation 2x3 − 3xy + y3 = −1 at the point (2, −3).
negative eleven sevenths
5 over 7
negative 1 over 3
4 over 3 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the slope of the graph of the relation 2x3 − 3xy + y3 = −1 at the point (2,−3).
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Use ^ (Shift 6) for exponents.
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2x^3 − 3xy + y^3 = −1
Differentiate implicitly.
6x^2dx - 3(ydx + xdy) + 3y^2dy = 0
2x^2dx - ydx - xdy + y^2dy = 0
2x^2dx - ydx = xdy - y^2dy
(2x^2 - y)dx = (x - y^2)dy
dy/dx = (2x^2 - y)/(x - y^2)
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That's the slope, but (2,-3) is not a point on the curve.
