SOLUTION: With a headwind, a small plane can fly 240 miles in 3 hours. With a tailwind the plane can fly the same distance in 2 hours.
Let p be the rate of the plane and w be the rate of
Algebra ->
Expressions-with-variables
-> SOLUTION: With a headwind, a small plane can fly 240 miles in 3 hours. With a tailwind the plane can fly the same distance in 2 hours.
Let p be the rate of the plane and w be the rate of
Log On
Question 966424: With a headwind, a small plane can fly 240 miles in 3 hours. With a tailwind the plane can fly the same distance in 2 hours.
Let p be the rate of the plane and w be the rate of the wind.
Rate Multiplied with Time Equals Distance
With Headwind p-w * 3 = 240
With Tailwind p-w * 2 = 240
Use the information in each row to write a system of equations
Solve the system of equations the find the rates of the plane and wind
You can put this solution on YOUR website! With a headwind, a small plane can fly 240 miles in 3 hours. With a tailwind the plane can fly the same distance in 2 hours.
Let p be the rate of the plane and w be the rate of the wind.
Rate Multiplied with Time Equals Distance
With Headwind p-w * 3 = 240
With Tailwind p-w * 2 = 240 *********** Should be p+w
Use the information in each row to write a system of equations
Solve the system of equations the find the rates of the plane and wind
================
The plane's airspeed is the average of the groundspeeds, upwind and downwind.
--------
Wind speed is the difference between airspeed and groundspeed.
================
