Question 869669: (3x^2y)(-2xy^5)
Please simply the exponential expression.
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! The idea is to group the like terms together, then multiply them. So 3 and -2 are like terms. They multiply to -6. The terms x^2 and x are like terms, they multiply to x^3, etc etc
(3x^2y)(-2xy^5)
(3*(-2)) * (x^2*x) * (y*y^5)
(-6) * (x^2*x) * (y*y^5)
(-6) * (x^2*x^1) * (y^1*y^5)
(-6) * x^(2+1) * y^(1+5)
-6*x^3*y^6
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