SOLUTION: Sprinter A runs 100 meters in 15 seconds, while sprinter B starts 1.5 seconds later and runs 100 meters in 14 seconds. If each of them runs at a constant rate, who is further in 10
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-> SOLUTION: Sprinter A runs 100 meters in 15 seconds, while sprinter B starts 1.5 seconds later and runs 100 meters in 14 seconds. If each of them runs at a constant rate, who is further in 10
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Question 812599: Sprinter A runs 100 meters in 15 seconds, while sprinter B starts 1.5 seconds later and runs 100 meters in 14 seconds. If each of them runs at a constant rate, who is further in 10 seconds after the start of the race? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! s = d / t
d = s * t
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a = 100/15 m/sec
b = 100/14 m/sec
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at 10 seconds:
a has run a distance of:
d = (100/15) * 10 = 66.7 meters
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at 10 seconds:
b has only been running for 8.5 seconds and so has run a distance of:
d = (100/14) * 8.5 = 60.7 meters
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Answer:
at 10 seconds A is ahead of B by 6 meters
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