SOLUTION: How do you solve the system of equations below for a and b: 32=a*b^2 128=a*b^3

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Question 805721: How do you solve the system of equations below for a and b:
32=a*b^2
128=a*b^3
Found 2 solutions by Alan3354, KMST:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
32=a*b^2
128=a*b^3
------------
128=a*b^3
32=a*b^2
------------ Divide
4 = b
a = 2

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Dividing the second equation by the first,
128%2F32=a%2Ab%5E3%2F%28a%2Ab%5E2%29
4=b
highlight%28b=4%29
Then, substituting that value for b
32=a%2A4%5E2
32=16a
a=32%2F16
highlight%28a=2%29