SOLUTION: Sammy bought DVDs and CDs. She spent the same amount of money on both. If DVDs cost $16 and CDs cost $12, what is the least she could have spent total?

Algebra ->  Expressions-with-variables -> SOLUTION: Sammy bought DVDs and CDs. She spent the same amount of money on both. If DVDs cost $16 and CDs cost $12, what is the least she could have spent total?      Log On


   

Question 629722: Sammy bought DVDs and CDs. She spent the same amount of money on both. If DVDs cost $16 and CDs cost $12, what is the least she could have spent total?
Found 2 solutions by ewatrrr, josmiceli:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Sammy bought DVDs and CDs. She spent the same amount of money on both

cost $16 and CDs cost $12, what is the least she could have spent total

16%2A3+%2B+12%2A4+=+96    ||48 being the LCM

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = the number of DVD's she bought
Let +b+ = the number of CD's she bought
given:
+16a+=+12b+ ( she spent the same on each )
+a%2Fb+=+12%2F16+
+a%2Fb+=++3%2F4+
3 DVDs and 4 CDs is the least she could have bought
+3%2A16+%2B+4%2A12+=+48+%2B+48+
+2%2A48+=+96+
The least she could have spent total was $96