SOLUTION: Nelson wants to use a few pieces of silver to make a bracelet. Some of the jewelry is 70% silver, and the rest is 58% silver. Nelson needs 26.00g of 65% silver. How much of each al
Algebra.Com
Question 620242: Nelson wants to use a few pieces of silver to make a bracelet. Some of the jewelry is 70% silver, and the rest is 58% silver. Nelson needs 26.00g of 65% silver. How much of each alloy should he use?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
elson wants to use a few pieces of silver to make a bracelet.
Some of the jewelry is 70% silver, and the rest is 58% silver.
Nelson needs 26.00g of 65% silver. How much of each alloy should he use?
;
Let x = amt of 70% silver
the total amt is to be 26 gr, therefore:
(26-x) amt of 58% silver
:
A typical mixture equation
:
.70x + .58(26-x) = .65(26)
.70x + 15.08 - .58x = 16.9
.70x - .58x = 16.9 - 15.08
.12x = 1.82
x = 1.82/.12
x = 15 gr of 70% silver
and
26 - 15 = 10 gr of 58% silver
RELATED QUESTIONS
Bachelle wants to know the density of her bracelet, which is a mix of gold and silver.... (answered by ikleyn)
A jeweler plans to combine two silver alloys to make 50 grams of alloy that is 75% silver (answered by josmiceli,ankor@dixie-net.com)
A craftperson has two alloys of silver. The first on is 70% pure silver and the second... (answered by ewatrrr)
Suppose you have 10 ounces of jewelry silver how much pure silver must be mixed with the... (answered by josgarithmetic)
Twenty ounces of pure silver are added to 70 oz of a silver alloy that is 10% silver.... (answered by josgarithmetic)
A jeweler melts down 90 grams of jewelry that is made of an alloy of 20% silver and 80%... (answered by ankor@dixie-net.com)
A person wants to make a one ounce ring composed of Gold and Silver. One ounce of gold... (answered by stanbon)
a gold bracelet cost $20 more than ten times the cost of silver earrings. the cost of... (answered by fractalier)
Write a linear equation to model this situation. An alloy is a mixture of metals. An... (answered by Theo)