SOLUTION: if a rectangular table with an area of 35sq ft has a width that is 2 ft less than the length what are the dimensions of the table.
I think it is written
2(l x l-2)=35 let
Algebra ->
Expressions-with-variables
-> SOLUTION: if a rectangular table with an area of 35sq ft has a width that is 2 ft less than the length what are the dimensions of the table.
I think it is written
2(l x l-2)=35 let
Log On
Question 517951: if a rectangular table with an area of 35sq ft has a width that is 2 ft less than the length what are the dimensions of the table.
I think it is written
2(l x l-2)=35 let me know if I doing this right and I need help with steps Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! L=X
W=X-2
AREA=LW
35=X(X-2)
35=X^2-2X
X^2-2X-35=0
(X-7)(X+5)=0
X-7=0
X=7 ANS. FOR THE LENGTH.
7-2=5 ANS. FOR THE WIDTH.
35=7(7-5)
35=7*5
35=35