SOLUTION: An ice hockey rink is a rectangle with a perimeter of 174 meters. The length is 9 meters more than twice the width. Find the length and width?

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Question 421802: An ice hockey rink is a rectangle with a perimeter of 174 meters. The length is 9 meters more than twice the width. Find the length and width?
Found 2 solutions by stanbon, Adrish:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An ice hockey rink is a rectangle with a perimeter of 174 meters. The length is 9 meters more than twice the width. Find the length and width?
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Perimeter = 2(width + length)
Let width = x
Then length = 2x+9
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174 = 2(x + 2x+9)
87 = 3x+9
3x = 78
x = 26
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Width = 26 meters
Length = 2x+9 = 52+9 = 61 meters
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Cheers,
Stan H.
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Answer by Adrish(44) About Me  (Show Source):
You can put this solution on YOUR website!
Solutions: Let the width be "x"
and the length be 9+2w
Given:Perimeter=174 meters
we know Perimeter of rectangle=2L + 2W
P=2Lx 2W
174=2(9+2w) + 2w
174=18 +4w +2w
174=18+6w
6w=174-18
6w=156
w=156/6
w=26
Therefore Width=26 meter
Length=9+2w=9+2x26
=9+ 52
=61 meter