SOLUTION: a jar containing only nickels and dimes contains 60 coins. The value of all the coins in the jar is $4.45. solve by elimination to find the amount of nickels and dimes are in the j

Algebra ->  Expressions-with-variables -> SOLUTION: a jar containing only nickels and dimes contains 60 coins. The value of all the coins in the jar is $4.45. solve by elimination to find the amount of nickels and dimes are in the j      Log On


   

Question 290807: a jar containing only nickels and dimes contains 60 coins. The value of all the coins in the jar is $4.45. solve by elimination to find the amount of nickels and dimes are in the jar
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
N+D=60 MULTIPLY THIS EQUATION BY -.05 & ADD
.05N+.10D=4.45
-.05N-.05D=-3
-----------------
.05D=1.45
D=1.45/.05
D=29 DIMES.
60-29=31 NICKELS.
PROOF:
.05*31+.10*29=4.45
1.55+2.90=4.45
4.45=4.45