SOLUTION: The sum of the integers from 1 to n is n(n+1) over 2. The sum of the squares of the integers from 1 through n is n(n+1)(2n+1) over 6 . The sum of the cubes of the integers from 1

Algebra ->  Expressions-with-variables -> SOLUTION: The sum of the integers from 1 to n is n(n+1) over 2. The sum of the squares of the integers from 1 through n is n(n+1)(2n+1) over 6 . The sum of the cubes of the integers from 1       Log On


   



Question 251885: The sum of the integers from 1 to n is n(n+1) over 2. The sum of the squares of the integers from 1 through n is n(n+1)(2n+1) over 6 . The sum of the cubes of the integers from 1 through n is n^2(n+1)^2 over 4 . Use the appropriate expressions to find the following values.
A. The sum of the integers from 1 to 30.
i just dont underatand what it wants me to do, i looked in the book but i cant find any examples to help explain what i am suppose to even solve. I am just not sure where i should even start.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Add up the integers 12,3,4,5...28, 29,30 using the formula
Sum(n)=n(n+1)/2
30*31/2=15*31