SOLUTION: # 7. A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third s
Algebra ->
Expressions-with-variables
-> SOLUTION: # 7. A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third s
Log On
Question 190615: # 7. A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third side is 4 meters more than the first side. Find the length in meters of each side of the triangular region
You can put this solution on YOUR website! # 7
Q: A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third side is 4 meters more than the first side. Find the length in meters of each side of the triangular region
A:
Let
x = length of first side
y = length of second side
z = length of third side
Since "The second side is one-fourth of the first side in length", this means that
Also, since "The third side is 4 meters more than the first side", this means
Finally, because "The perimeter of the triangle is 49 meters", this tells us that
Start with the third equation.
Plug in and
Multiply EVERY term by the LCD to clear the fraction.