SOLUTION: This is dividing, the question before that I got it right, but with this dividing problem. Very difficult for me. So I have to divide 2x^2y-6xy^2+12xy/2xy, I did try to solve it

Algebra ->  Expressions-with-variables -> SOLUTION: This is dividing, the question before that I got it right, but with this dividing problem. Very difficult for me. So I have to divide 2x^2y-6xy^2+12xy/2xy, I did try to solve it       Log On


   

Question 147447This question is from textbook algebra
: This is dividing, the question before that I got it right, but with this dividing problem. Very difficult for me. So I have to divide
2x^2y-6xy^2+12xy/2xy, I did try to solve it and got xy+3^2-6 obviously it's wrong, So can someone please help me. Thank you=) This question is from textbook algebra

Found 2 solutions by vleith, jim_thompson5910:
Answer by vleith(2983) About Me  (Show Source):
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%282x%5E2y-6xy%5E2%2B12xy%29%2F%282xy%29 Start with the given expression.


%282x%5E2y%29%2F%282xy%29-%286xy%5E2%29%2F%282xy%29%2B%2812xy%29%2F%282xy%29 Break up the fraction.


%282x%2Ax%2Ay%29%2F%282xy%29-%286x%2Ay%2Ay%29%2F%282xy%29%2B%2812xy%29%2F%282xy%29 Expand. Remember, x%5E2=x%2Ax and y%5E2=y%2Ay


Factor 6 to get 2*3 and factor 12 to get 2*6. Notice how I'm factoring out 2's from each number.




Highlight the common terms.



Cancel out the common terms.


x-3y%2B6 Simplify.


So %282x%5E2y-6xy%5E2%2B12xy%29%2F%282xy%29 simplifies to x-3y%2B6


In other words, %282x%5E2y-6xy%5E2%2B12xy%29%2F%282xy%29=x-3y%2B6 where x%3C%3E0 or y%3C%3E0