SOLUTION: The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=1 and x=0, and a root of multiplicity 1 at x=−3 Find a possible formula for P(x).

Algebra ->  Expressions-with-variables -> SOLUTION: The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=1 and x=0, and a root of multiplicity 1 at x=−3 Find a possible formula for P(x).       Log On


   

Question 1200216: The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=1 and x=0, and a root of multiplicity 1 at x=−3
Find a possible formula for P(x).

Answer by ikleyn(52824) About Me  (Show Source):
You can put this solution on YOUR website!
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At given conditions, a possible formula for P(x) is

    P(x) = x%5E2%2A%28x-1%29%5E2%2A%28x%2B3%29.


As a product of elementary binomial factors, this formula is UNIQUE.


You can transform it to any other equivalent form opening brackets (making FOIL).

Solved.