SOLUTION: A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much

Algebra ->  Expressions-with-variables -> SOLUTION: A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much      Log On


   



Question 1194902: A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much money was invested in each account?


Which of the following equations could be used to solve the problem?
0.02x + 0.04(800) = 112
0.04x + 0.02(x + 800) = 112
0.02x + 0.04(x + 800) = 112

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
it can be x for the smaller account at 0.02
and x+800 for the larger account at 0.04
The total is 0.02x0+0.04(x+800)=112
C,